From Trinity College Cambridge

@zaahir on keybase

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$${\displaystyle {\displaystyle \cdots \stackrel{\partial }{\to }{\tilde{h}}_n(A)\stackrel{i_{\ast }}{\to }{\tilde{h}}_n(X)\stackrel{q_{\ast }}{\to }{\tilde{h}}_n(X/A)\stackrel{\partial }{\to }{\tilde{h}}_{n-1}(A)\stackrel{i_{\ast }}{\to }\dots }}$$

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