Consider a sequence of integers, containing integers between and . Each integer appears exactly once in the sequence.
A subsequence of is a sequence obtained by removing some (possibly none) numbers from the beginning of , and then from the end of . Calculate how many different subsequences of of odd length have their median equal to . The median of a sequence is the element in the middle of the sequence after it is sorted. For example, the median of the sequence is .
Input Specification
The first line contains two integers, and .
The second line contains integers separated by spaces, the elements of sequence .
Output Specification
Output the number of subsequences of whose median is .
Sample Input 1
5 4
1 2 3 4 5
Sample Output 1
2
Sample Input 2
6 3
1 2 4 5 6 3
Sample Output 2
1
Sample Input 3
7 4
5 7 2 4 3 1 6
Sample Output 3
4
Explanation for Sample Output 3
In the third example, the four subsequences of with median are , , and .
Comments
I currently have an algorithm in Python. Is there a better time complexity in which I can solve it? or is Python just too slow for this problem?
Since , can be in a worst case, which is too slow.