Editorial for WC '17 Finals J1 - Cownterintelligence
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Submitting an official solution before solving the problem yourself is a bannable offence.
        Submitting an official solution before solving the problem yourself is a bannable offence.
Upon inputting each cow 's moo frequency 
, we'll need to determine whether it's a power-of-
 multiple of 
, and output the number 
 if it's not.
One way to check this is to initialize a variable  to be equal to 
, and then repeatedly multiply 
 by 
 while checking if it's equal to 
 at each iteration. If we do find a value of 
 which is equal to 
, then we know that cow 
 isn't an imposter, and we'll want to skip over it. On the other hand, if 
 never becomes equal to 
 and instead gets to be larger than 
, then we know that cow 
 is an alien imposter.
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