Valentine's Day '18 J1 - The Cactus Number - Olympiads Online Judge

Valentine's Day '18 J1 - The Cactus Number

Points: 3 (partial)

Time limit: 1.0s

Memory limit: 64M

Author:

Problem type

Being a cuteness connoisseur, Carol has devised a system of measuring cuteness called "Carol Numbers", where one Carol number represents her own cuteness in a natural state.

Cactus numbers are said to represent ten times the cuteness as a Carol number. Some say that Cactus numbers do not exist, as a Carol number should be the highest conceivable value of cuteness. You will receive $N$ $N$ Carol numbers, given in insignificant units as there are rarely Carol numbers above $1$ $1$ . One insignificant Carol is $1/1000$ $1 / 1000$ of a Carol. Is the Carol number truly the highest possible cuteness?

Constraints

$1 \le N, K_i \le 10^6$ $1 \leq N, K_{i} \leq 10^{6}$

Input Specification

The first line will contain $N$ $N$ , the number of values.

Each of the following $N$ $N$ lines will contain an integer $K_i$ $K_{i}$ , representing the $i^\text{th}$ $i^{th}$ Carol number, represented as cuteness in insignificant Carols.

Output Specification

If any Carol number above 10 exists, output Something is wrong with these cuteness values.

If any Carol number above 1 exists, but no Carol number above 10 exists, output Cuteness by definition is similarity to Cactus.

If no Carol numbers above 1 exist, output Cuteness by definition is similarity to Carol.

Sample Input 1

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Sample Output 1

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Cuteness by definition is similarity to Carol

Sample Input 2

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Sample Output 2

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Cuteness by definition is similarity to Cactus

Comments

0

candyappled commented on Jan. 27, 2022, 2:07 a.m.

I'm failing cases 2, 9, 13 and 15. Can someone tell me what's wrong?

0

Spitfire720 commented on Jan. 27, 2022, 1:45 p.m.

Your code will fail when the max is 10000

0

Julien commented on Jan. 9, 2020, 9:20 p.m.

Does anyone know how I can get past a TLE?

3
Dingledooper commented on Jan. 9, 2020, 11:46 p.m.
Put these two lines at the beginning of your code. The input will be faster.

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import sys input = sys.stdin.readline