## CCC '20 S2 - Escape Room

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Points: 7 (partial)
Time limit: 2.0s
Memory limit: 512M

Problem type
##### Canadian Computing Competition: 2020 Stage 1, Junior #5, Senior #2

You have to determine if it is possible to escape from a room. The room is an -by- grid with each position (cell) containing a positive integer. The rows are numbered and the columns are numbered . We use to refer to the cell in row and column .

You start in the top-left corner at and exit from the bottom-right corner at . If you are in a cell containing the value , then you can jump to any cell satisfying . For example, if you are in a cell containing a , you can jump to cell .

Note that from a cell containing a , there are up to four cells you can jump to: , or . If the room is a -by- grid, there isn't a row so only the first three jumps would be possible.

#### Input Specifcation

The first line of the input will be an integer . The second line of the input will be an integer . The remaining input gives the positive integers in the cells of the room with rows and columns. It consists of lines where each line contains positive integers, each less than or equal to , separated by single spaces.

For of the available marks, and .

For an additional of the available marks, .

For an additional of the available marks, all of the integers in the cells will be unique.

For an additional of the available marks, and .

#### Output Specification

Output yes if it is possible to escape from the room. Otherwise, output no.

#### Sample Input

3
4
3 10 8 14
1 11 12 12
6 2 3 9

#### Output for Sample Input

yes

#### Explanation of Output for Sample Input

Starting in the cell at which contains a , one possibility is to jump to the cell at . This cell contains an so from it, you could jump to the cell at . This brings you to a cell containing from which you can jump to the exit at . Note that another way to escape is to jump from the starting cell to the cell at to the cell at to the exit.

Notes

1. The online grader begins by testing submissions using the sample input. All other tests are skipped if the sample test is not passed. If you are only attempting the first three subtasks (the first marks), then you might want to handle the specific values of the sample input as a special case.

2. For the final subtask (worth marks), if you are using Java, then Scanner will probably take too long to read in the large amount of data. A much faster alternative is BufferedReader.

• kevze  commented on March 28, 2020, 5:18 p.m.

I'm having trouble staying below the memory limit. Can someone give me a hint?

• detas  commented on March 27, 2020, 11:07 p.m.

how to not tle on batch 7?

• Ibby  commented on March 28, 2020, 8:29 p.m.

Your getPairs function looks through 1 to N for every space added to the queue which is too slow. Try finding a faster way to look for factors.

• RIPRoyale  commented on March 26, 2020, 3:47 p.m.

My code gives a NameError on the first case? It woks fine on the CCC Grader.

• Xyene  commented on March 26, 2020, 3:52 p.m.

Using site functions (like exit)

The DMOJ denies access to the site module, so functions that are injected into the builtin namespace — like exit — are disallowed.

• devnarula  commented on March 25, 2020, 11:24 p.m.

Can anyone explain why I am getting TLE at the end of Batch 6 even though I am just implementing BFS on my program (c++)

• Dingledooper  commented on March 25, 2020, 11:42 p.m.

It is because your BFS function contains a searchm function which runs in every iteration, probably taking up to .

• Ibby  commented on March 25, 2020, 10:26 p.m.

TFW you spent 40 whole minutes during the CCC thinking you can only jump to adjacent cells.

• LordTachankaTM  commented on March 25, 2020, 7:01 p.m. edit 2

Disregard this comment, I'm blind.

• harry7557558  commented on March 25, 2020, 6:49 p.m.

AC in CCC and TLE on DMOJ. (finally solved it)

• pblpbl  commented on March 25, 2020, 6:21 p.m.

Any tips on how to not TLE even with C++?

• ross_cleary  commented on March 25, 2020, 6:31 p.m.

Having a loop to find all the factors of the number in the current cell is too slow. Try to find an approach that avoids this.

• pblpbl  commented on March 25, 2020, 7:46 p.m.

ok thanks

• alihu264  commented on March 28, 2020, 5:21 p.m.

You could do it relatively fast if you just precompute the factors when you're taking input