Comments

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  -7

  

  andrue111  commented on Sept. 28, 2024, 8:31 p.m. ← edited →

  text = str(input())
  
  happy = int(text.count(':-)'))
  sad = int(text.count(':-('))
  
  if happy == 0 and sad == 0:
      print('none')
  elif happy == sad:
      print('unsure')
  elif happy > sad:
      print("happy")
  elif sad > happy:
      print('sad')
  

  This comment is hidden due to too much negative feedback. Show it anyway.

• 
  

  -11

  

  Eason_liu_python  commented on Sept. 13, 2024, 1:36 a.m. ← edited →

  this is the perfect version gets you 100%:

  a = str(input())
  happy = int(a .count(":-)"))
  sad = int(a .count(":-("))
  
  if happy > sad:
      print("happy")
  elif sad > happy:
      print("sad")
  elif sad == 0 and happy == 0:
      print("none")
  else:
      print("unsure")
  

  This comment is hidden due to too much negative feedback. Show it anyway.

• 
  

  -3

  

  aimalie98  commented on Oct. 25, 2023, 5:56 p.m. ← edited →

  I am super stuck on this problem and I don't know how to fix it. I have just learned about and, if statements but have not encountered loops or length functions yet so I am with a very light tool belt to solve this problem. Is there a hint for a very very simple code to count the number of happy and sad faces?

  This was my best guess:

  line = str(input())
  
  if line .count(':-)') == 0 or line .count(':-(') == 0:
  
      print('none')
  
  elif line .count(':-)') == line .count(':-('):
  
      print('unsure')
  
  elif line .count(':-)') > line .count(':-('):
  
      print('happy')
  
  
  elif line .count(':-)') < line .count(':-('):
  
      print('sad')
  

• 
  

  -3

  

  JoeP  commented on Nov. 19, 2023, 12:26 p.m. ← edit 2 →

  aimalie98 I just tryed your code with and in stead of you "or" in the first if sentence and it is judged AC in all trials! So thank you for showing me how it can be written better that I have done it. JoeP

• 
  

  -4

  

  JoeP  commented on Nov. 19, 2023, 12:17 p.m. ← edit 2 →

  aimalie98! your code line that reads: "if line .count(':-)') == 0 or line .count(':-(') == 0:" should be: if line .count(':-)') == 0 and line .count(':-(') == 0: in stead for print('none') corresponds to the case when both sad and happy are zero and in your way of putting it when only one is zero so the program will return answer "none". That is the error I put my eye on but there are surely other that may have written this problem even better. My code that reads as follows:

  string = str(input())
  g = int(string .count(':-)'))
  s = int(string .count(':-('))
  
  if g > s:
      print('happy')
  elif s > g:
      print('sad')
  elif s == g:
      print('unsure')
  elif s == 0 and g == 0:
      print('none')
  

  returns one WA and the rest AC i.e. 13 of possible 15 score. And I do not know whats wrong with it? Can you come with the answer??!!!

• 
  

  0

  

  Daquine  commented on Dec. 14, 2023, 9:57 p.m. ← edited →

  Technically, the code is correct, it's the order in which each if statement is written out (although I changed it up just a bit).

  the order is:

  if happy < 1 and sad < 1: 
      print('none')
  elif sad == happy:
      print('unsure')
  elif happy > sad:
      print('happy')
  elif sad > happy:
      print('sad')
  

  I posted it in this order and I got all of them correct.

  This whole thread really helped me too, because I was lost with doing strings, and not just integers.

• 
  

  0

  

  曲意  commented on April 3, 2024, 11:50 a.m. ← edit 2 →

  I think the right answer is this:

  n1 = a.count(":-)")
  n2 = a.count(":-(")
  
  if n1 + n2 != 0: